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fredd [130]
3 years ago
14

Walleye is a common game fish. Adult walleye have a length with a mean of 44 cm and a standard deviation of 4 cm, and the distri

bution of lengths is approximately Normal. What fraction of fish are greater than 41 cm in length?
Select one O a. -0.75 O b. 0.22 ? ?.077 O d. 0.75
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:b. 0.22

Step-by-step explanation:

Since the lengths of adult walleye fishes are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = lengths of walleye fishes.

µ = mean length

σ = standard deviation

From the information given,

µ = 44 cm

σ = 4 cm

We want to find the probability or fraction of fishes that are greater than 41 cm in length. It is expressed as

P(x > 41) = 1 - P(x ≤ 41)

For x = 41,

z = (41 - 44)/4 = - 0.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.22

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Answer:

b║f

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Step-by-step explanation:

Given a diagram,

Lines b, c, d, e, f and a transversal line 'a'.

Here line 'b' makes an angle with line 'a' is 89.5° and line 'f' makes an angle with line 'a' is also 89.5° (180°-90.5° = 89.5°)

Since corresponding angles are same.

So, line 'b' is parallel to line 'f'.

And line 'c' makes an angle with line 'a' is 91.5° and line 'e' makes an angle with line 'a' is also 91.5° (180°-88.5° = 91.5°)

Since corresponding angles are same.

So, line 'c' is parallel to line 'e'.

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Explicación paso a paso:

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