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3 years ago

5 ( f + 4) = 4 ( f - 6)

Mathematics

2 answers:

jekas [21]3 years ago

6 0

f = -44

Hope this helps :)

enot [183]3 years ago

4 0

Answer:

The answer is -44

Step-by-step explanation:

First, you use distributive property on each side.

5xf + 5x4 = 4xf-4x6

5f+20=4f-24

Then you subttract 5f to both sides of the equation.

5f+20=4f-24

-5f -5f

20=-1f-24

Next, you add 24 to both sides of the equation.

20=-1f-24

+24 +24

44=-1f

Finally, you divide -1f from each side of the equation.

44=-1f

/-1f /-1f

Your final answer should be -44=f

or f = -44

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Step-by-step explanation:

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3 years ago

To what expression must 5a square-4a+3 be added to make the sum zero??

pychu [463]

Answer:

Step-by-step explanation:

Additive inverse of (5a² - 4a + 3) should be added to make them zero

(5a² - 4a + 3) + (-5a² + 4a - 3)= 5a² - 5a² - 4a + 4a + 3 - 3

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2 years ago

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2 years ago

Does anyone know What does x equal?

vazorg [7]

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3 years ago

What basic trigonometric identity would you use to verify that

Dafna1 [17]

Given the equation:

$\frac{\sin^2x+\text{cos}^2x}{\cos x}=\sec x$

Let's determine the trigonometric identity that you could be used to verify the exquation.

Let's determine the identity:

Apply the trigonometric identity:

$\sin ^2x+\cos ^2x=1$

$\cos x=\frac{1}{\sec x}$

Replace cosx for 1/secx

Thus, we have:

$\begin{gathered} \frac{\sin^2x+\cos^2x}{\frac{1}{\sec x}} \\ \\ =(\sin ^2x+\cos ^2x)(\sec x) \\ \text{Where:} \\ (\sin ^2x+\cos ^2x)=1 \\ \\ We\text{ have:} \\ (\sin ^2x+\cos ^2x)(\sec x)=1\sec x=\sec x \end{gathered}$

The equation is an identity.

Therefore, the trignonometric identity you would use to verify the equation is:

$\cos ^2x+\sin ^2x=1$

ANSWER:

$\cos ^2x+\sin ^2x=1$

6 0

1 year ago