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Svet_ta [14]
3 years ago
5

Match each function formula with the corresponding transformation of the parent function y = (x - 1)2 1. y = - (x - 1)2 Reflecte

d over the y-axis 2. y = (x - 1)2 + 1 Reflected over the x-axis 3. y = (x + 1)2 Translated right by 1 unit 4. y = (x - 2)2 Translated down by 3 units 5. y = (x - 1)2 - 3 Translated up by 1 unit 6. y = (x + 3)2 Translated left by 4 units
Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

  1. y = -(x-1)² . . . . reflected over the x-axis
  2. y = (x-1)² +1 . . . . translated up by 1 unit
  3. y = (x+1)² . . . . reflected over the y-axis
  4. y = (x-2)² . . . . translated right by 1 unit
  5. y = (x-1)² -3 . . . . translated down by 3 units
  6. y = (x+3)² . . . . translated left by 4 units

Step-by-step explanation:

Since you have studied transformations, you are familiar with the effect of different modifications of the parent function:

  • f(x-a) . . . translates right by "a" units
  • f(x) +a . . . translates up by "a" units
  • a·f(x) . . . vertically scales by a factor of "a". When a < 0, reflects across the x-axis
  • f(ax) . . . horizontally compresses by a factor of "a". When a < 0, reflects across the y-axis.

Note that in the given list of transformed functions, there is one that is (x+1)². This is equivalent to both f(x+2) and to f(-x). The latter is a little harder to see, until we realize that (-x-1)² = (x+1)². That is, this transformed function can be considered to be either a translation of (x-1)² left by 2 units, or a reflection over the y-axis.

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Find the value of y.
Phoenix [80]

\boxed{y=6\sqrt{3}}

<h2>Explanation:</h2>

For a better understanding of the problem I've built up two triangles from the given triangular shape. So these two triangles are similar. Therefore, we can solve this problem by using ratios and corresponding sides in this way:

\frac{x}{3}=\frac{12}{x} \\ \\ x^2=36 \\ \\ x=\sqrt{36} \\ \\ x=6

But our goal is to find y. Let's call w the height of the small triangle, then:

w=\sqrt{6^2-3^2}=3\sqrt{3}

Applying the concept of ratios again:

\frac{y}{w}=\frac{x}{3} \\ \\ y=w \left(\frac{x}{3}\right) \\ \\ y=3\sqrt{3}\left(\frac{6}{3}\right) \\ \\ \boxed{y=6\sqrt{3}}

<h2>Learn more:</h2>

Right triangle: brainly.com/question/10684799

#LearnWithBrainly

4 0
3 years ago
Long division 5th grade I’m sorry if I’m asking a lot but I’m really new to this
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95.2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find the standard equation of a circle that passes through the point (−1, 1) with center (2, 3).
Firlakuza [10]
The equation of a circle is
  (x-h)² + (y-k)² = r²
for center (h, k) and radius r. Of course, the radius can be computed by putting the point in the equation.
  (x-2)² + (y-3)² = (-1-2)² + (1-3)² = 9+4 = 13

The standard equation of the circle is (x-2)² + (y-3)² = 13.

6 0
3 years ago
Last 2 questions please help
Jlenok [28]
4.
Minimum: 20
First Quartile: 44
Median: 51
Third Quartile: 57
Maximum: 86

Ascending order : 20 41 44 44 49 53 55 57 80 86
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2 years ago
En un curso hay 11 mujeres y 13 hombres. Si se eligen dos alumnos para representarlos en el campeonato de debate, ¿cuál es la pr
Tresset [83]

Answer:

106.34%  

Step-by-step explanation:

hay 24 personas en total (11 mujeres+13 hombres)

la probabilidad para que uno de los alumnos es un hombre es 13/24 (porque hay 13 hombres en la clase)

Entonces, si uno hombre está elegido, quedan 12 hombres, así que, la probabilidad si es un hombre es 12/23 (porque una persona ya está elegido y quedan 23 personas)

la probabilidad es 13/24+12/23=587/552=106.34%  (Redondeado a la décima más cercana)

(lo siento mi español no es perfecto)

8 0
2 years ago
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