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Ket [755]
3 years ago
12

Find the probability of each compound event

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

which ones?

Step-by-step explanation:

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What is 95% of 85?<br> HELP ME PLZZZZ
Nimfa-mama [501]
95%=0.95 so... .95•85= 80.75
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Translate: twice the sum of a number and 9 equals 7 into an equation
Ghella [55]
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3 years ago
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Hunter-Best [27]

<u>Answer:</u>

x = 20; ∠5 = 120°

<u>Step-by-step explanation:</u>

∠1 and ∠8 are alternate angles and therefore are equal, which means that if m ∠1 = (4x + 40)° and m ∠8 = (2x + 80)°, then 4x + 40 = 2x + 80

Solve for x:

4x + 40 = 2x + 80

2x = 40

x = 20

∠5 is corresponding to ∠1 and vertical to ∠8, therefore equal to both; To find it's measure:

Plug x into either ∠1 or ∠8's respective equations:

2x + 80  

2(20) + 80

120

∠5 is 120°

8 0
2 years ago
The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour
vitfil [10]

Z value is a numerical  measurement that describe a value relationship to the mean of a group of values. The standard deviations is 1.25 above the mean is 14,500 hours.

<h3>Given information-</h3>

The mean for the bulb is 12,000 hours.

The standard deviation for the bulb is 2000 hours.

Sample value is 14500.

To find out the how many standard deviation is 14500 mean away from the mean the z value of the mean should be calculated.

<h3>Z value</h3>

Z value is a numerical  measurement that describe a value relationship to the mean of a group of values. Z value is the ratio of the difference of the sample value x and mean \mu to the standard deviation. Thus the z value for the given mean \sigma is,

z=\dfrac{x-\mu}{\sigma}

z=\dfrac{14500-1200}{2000}

z=1.25

Thus the standard deviations is 1.25 above the mean is 14,500 hours.

Learn more about the z value here;

brainly.com/question/62233

4 0
3 years ago
(4^7/5^2)^3 i Don't get it
jenyasd209 [6]

Answer:

\sf \dfrac{4^{21}}{5^6}

Step-by-step explanation:

Exponent Law:  

       \sf \boxed{\left(\dfrac{a^m}{b^n}\right)^{x}=\dfrac{a^{m*x}}{b^{n*x}}}

When any base is being multiplied by an exponent, distribute the exponent to each part of the base.

\sf \left(\dfrac{4^7}{5^2}\right)^{3}=\dfrac{4^{7*3}}{5^{2*3}}

           \sf =\dfrac{4^{21}}{5^6}

7 0
1 year ago
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