Question

Evaluate the limit as x goes to infinity of x^3e^-x/5

Answer 1

Answer: 0

Step-by-step explanation:

$\frac{x^{3}e^{-x}}{5}$

This could be written as

$\frac{x^{3} }{5e^{-x} }$

Applying L'H rule and differentiating 3 times , we have

$\frac{6}{5e^{x} }$

taking the limit as x goes to infinity , we have

0