4)
the arrow touches the ground when the heigth is 0
so we need to replace h=0 and solve for t
<em>the arrow tuches the ground at 3.4 seconds</em>
5)
replacing
<em>solve for m</em>
<em>the mass is 13.50Kg</em>
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- I) the probability that the person is female is 8.33%.
- II) the probability that the person has a risk factor heterosexual contact is 6.40%.
- III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
- IV) the probability that the person is female and has a risk factor of homosexual is 0%.
- V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
- VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.
Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:
I.-
(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X
255/3059 = X
0.0833 = X
II.-
196/3059 = X
0.0640 = X
III.-
(255 + 463) / 3059 = X
718/3059 = X
0.2347 = X
IV.-
0/3059 = X
0 = X
V.-
463/3059 = X
0.1513 = X
VI.-
136/196 = X
0.6938 = X
Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.
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