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Anni [7]
3 years ago
15

Who is sacatoa joe in geometry

Mathematics
1 answer:
valkas [14]3 years ago
3 0
I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such


anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent

(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
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What is the probability of spinning once and having it land on either 2 or 8?
Aloiza [94]
If the highest number is 8 then the answer I think would be 1/8.
6 0
3 years ago
Which of the following angles is coterminal with -4pi/3?<br><br> -2pi/3<br> -pi/3<br> pi/3<br> 2pi/3
PolarNik [594]
Coterminal angles are angles that end in the same position on a unit circle.

We can find angles that are coterminal to -4pi/3 by adding and subtracting 2pi.

-4pi/3 + 2pi = 2pi/3

The answer is 2pi/3
4 0
2 years ago
1(6x - 9) = (4x - 6)
ruslelena [56]

1(6x-9)=(4x-6)  

One solution was found :

                  x = 3/2 = 1.500

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    1*(6*x-9)-((4*x-6))=0  

Step by step solution :

Step  1  :

Step  2  :

Pulling out like terms :

2.1     Pull out like factors :

  6x - 9  =   3 • (2x - 3)  

Equation at the end of step  2  :

 3 • (2x - 3) -  (4x - 6)  = 0  

Step  3  :

Equation at the end of step  3  :

 2x - 3  = 0  

Step  4  :

Solving a Single Variable Equation :

4.1      Solve  :    2x-3 = 0  

Add  3  to both sides of the equation :  

                     2x = 3

Divide both sides of the equation by 2:

                    x = 3/2 = 1.500

One solution was found :

                  x = 3/2 = 1.500

3 0
2 years ago
Read 2 more answers
The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the s
gulaghasi [49]

Answer:

The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the sum of the numbers in the six outer circles of the star, must be equal to 26. Arrange the numbers accordingly.

4 0
1 year ago
Find a formula for the general term or of the sequence assuming the pattern of the first few terms
bearhunter [10]

Answer:5n+6

Step-by-step explanation :an=a1+d(n-1)

=1+(-5)(n-1) or 1+-5n+5

an=-5n+6

6 0
3 years ago
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