Ask question

Ask question

All categories

3 years ago

7

The sum of two integers is five the different is three what are the two integers

1 answer:

Elza [17]3 years ago

5 0

Think about it for a minute and take a deep breath. you’ll be ok. i’m solving it rn please give me a minute

You might be interested in

Help me please!!!!!!!!!!!

tangare [24]

Answer:

m∠B = 107°

Step-by-step explanation:

The given geometric figure is a deltoid or quadrilateral with two pairs of equal adjacent sides whose diagonals are perpendicular.

The longer diagonal divides two opposite angles into two equal parts, which means:

m∠A = 2 · 32 = 64°

m∠C = 2 · 41 = 82

Also the angles m∠B ≅ m∠D = x

The total sum of the inner angles in the quadrilateral is 360°, which means:

2 · x = 360 - ( 64 + 82) = 360 - 146 = 214 => x = 214/2 = 107°

m∠B = 107°

God with you!!!

7 0

3 years ago

The Garcia’s bought a washing machine for $435 and a clothes dryer for $395 bath prices include tax to deliver these items the s

Lelechka [254]

Answer:

870

Step-by-step explanation:

$435 + $395 = $830

$830 + $10 = $840

$2 x 15 = $30

$840 + $30 = $870

4 0

3 years ago

The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

What is the unit rate for the ratio 100 points/ 4 games?

wlad13 [49]

Answer:c

Step-by-step explanation:

7 0

3 years ago

HELP PLEASE!! i need help on A and B. PLEASE DONT ANSWER IF YOU DONT KNOW!!

alexandr1967 [171]

A.
( 2.5 , 11 )
( 5 , 11 )
( 4.5 , 8 )
( 2 , 8 )
( 7 , 11 )
( 7 , 8 )
( 12 , 11 )
( 4.5 , 6 )
( 4.5 , 2 )
( 2 , 2 )
( 2 , 6 )
( 8 , 2 )
( 8 , 6 )
( 11 , 1 )
( 11 , 7 )

4 0

3 years ago