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sineoko [7]
3 years ago
12

-3.667987=b^(-2)w+(-1.981902-w)

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

what are the answers?

Step-by-step explanation:

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Step-by-step explanation:

Fill in your equation like this:

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How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

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2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

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5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
11 months ago
F(x) = 3x^4 + 19x^3 + 69x^2 + 99x + 26
bagirrra123 [75]

Answer:

sorry

Step-by-step explanation:

3 0
3 years ago
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