-3.667987=b^(-2)w+(-1.981902-w)
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Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).
Step-by-step explanation:
To solve this question, we can represent variables for the length and width in two equations.
To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:
Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:
This tells us that the width could be either 50 or 30.
Substitute 50 into one of the equations to find the length:
2 (l) + 100 = 160
l = 30.
The length and width are 50 and 30 meters (or 30 and 50 meters).