That looks hard... I can see the attachment tho<span />
<h2><em>each student requires 9m² of floor </em></h2><h2><em>and given the no. of students is 50
</em></h2><h2><em>So the total area of the room is 9m²X50=450m²
</em></h2><h2><em>Given the length of the room is 25m
</em></h2><h2><em>so the Breadth is =450/25=18m
</em></h2><h2><em>
</em></h2><h2><em>each student requires 108m³ of space </em></h2><h2><em>so total volume of the room is 108X50=5400m³
</em></h2><h2><em>we know that : Volume=Area X h
</em></h2><h2><em> so⇒5400=450Xh
</em></h2><h2><em> ⇒h=5400/450= 12m</em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
Answer:
Measures are SV=9 units., SY=14 units, YW=
, YW=
Step-by-step explanation:
Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.
As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.
Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.
Given ST=18 units.
As VY is perpendicular bisector implies SV=9 units.
Also in triangle VTY
⇒ 
⇒ VY^{2}=115
As vertices of triangle are equidistant from the circumcenter
⇒ SY=YT=UY=14 units
Hence, SY is 14 units
In ΔUWY, 
⇒ 
⇒ 
⇒ YW=
In ΔYXU, 
⇒ 
⇒ 
⇒ YW=
Hence, measures are SV=9 units., SY=14 units, YW= , YW=
Answer:
Step-by-step explanation:
Remark
My guess is that what is confusing you is not what you have to do, but why it is disguised as g(n)
What you are doing in effect is setting up a table. You are also not certain where the table starts. And that is a problem. I will start it at zero, but it might be 1.
zero
n = 0
g(0) = 34 - 5*0
g(0) = 34
One
n = 1
g(1) = 34 - 5*1
g(1) = 34 - 5
g(1) = 29
Two
g(2) = 34 - 5*2
g(2) = 34 - 10
g(2) = 24
Three
g(3) = 34 - 5*3
g(3) = 34 - 15
g(3) = 19
Four
g(4) = 34 - 5*4
g(4) = 34 - 20
g(4) = 19
Answer
0 1 2 3 4
34 29 24 19 14
