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den301095 [7]
2 years ago
15

Which of the following is the correct ordered pair when (-3,1) is rotated 270 degrees clockwise?

Mathematics
1 answer:
blsea [12.9K]2 years ago
3 0

Answer:

(-1,-3)

Step-by-step explanation:

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3Misty wants to save money to purchase a new bicycle that cost $279. She opens a savings account and deposits $7 per week. Based
Annette [7]

Answer:

it will take at least 10 weeks of saving to buy the bike

8 0
3 years ago
What are the solution(s) of –x2 + 2x + 3 = x2 – 2x + 3?
Leviafan [203]
-x^2+2x+3=x^2-2x+3  add x^2 to both sides

2x+3=2x^2-2x+3  subtract 2x from both sides

3=2x^2-4x+3  subtract 3 from both sides

2x^2-4x=0  factor

2x(x-2)=0

So x=0 and 2
3 0
3 years ago
Read 2 more answers
Consider this expression. -4x to the second power 2x - 5 (1 + x) What expression is equivalent to the given expression? blank x
iren [92.7K]

Answer:

what is the blank for

Step-by-step explanation:

sorry I mean bank

6 0
3 years ago
Solve for x. 3(3x - 1) + 2(3 - x) = 0
olga nikolaevna [1]
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
   = - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can always use this method for solving problems that are similar in type without requiring any help from outside. </span>



8 0
3 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n&#10;\\&#10;\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
3 years ago
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