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4 years ago

At what co2 concentration was stomata aperture width at its greatest? Lowest ?

Biology

1 answer:

Varvara68 [4.7K]4 years ago

8 0

Stomata aperture width is at its greatest when there is low concentration of CO2 in the atmosphere.

As the air's CO2 content rises, many plants reduce their stomatal apertures. As a result, plants growing in CO2-enriched air typically reduce the density of stomates on their leaf surfaces and as a consequence, exhibit reduced rates of transpirational water loss, smaller productivity losses attributable to the indiscriminate uptake of aerial pollutants, and increased water-use efficiency.

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3 years ago

Both processes shown below are energy conversion processes that take place inside of plant cells. Based on your knowledge of cel

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3 years ago

In a population of 10,000 individuals of Monstera deliciosa, four individuals have a variegated phenotype that is caused by the

Mariulka [41]

Under the assumption of this population being in Hardy-Weinberg equilibrium, the probability for the fixation of the var recessive allele equals 0.02 = 2%

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Available data:

N = 10,000 individuals ⇒ Large population

4 individuals have a variegated phenotype

variegated phenotype is caused by the recessive var allele

No selection, no additional mutation ⇒ we can assume Hardy-Weinberg equilibrium

We need to know the probability for the fixation of the var allele.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of variegated individuals in the population.

There are 10,000 individuals, and only 4 have variegated.

So, the phenotypic frequency, F(Var) is 4/10,000 = 0.0004 = 0.4%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(vv) = 0.4%

Finally, we can get the allelic frequency by taking the square root of this value.

F(vv) = q² = 0.0004

f(v) = q = √0.0004 = 0.02 = 2%

According to these calcs, the probability for the fixation of the var allele is 2%, and the probability that all individuals express the variegated phenotype is 0.4%.

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You can learn more about Hardy-Weinberg equilibrium at

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3 years ago

What is the difference between autosomes and a sex chromosome

Ray Of Light [21]

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4 years ago

In animals, if the fuel consumed exceeds energy expended, fats are synthesized from carbohydrates in order to store the excess e

Katen [24]

Answer:

B) Activation when the concentration of AMP is low vs concentration of ATP

Explanation:

The ACC enzyme is reserved by the AMP i.e. activated protein kinase (AMPK)

at the time when the AMP concentration is high because it represent the energy is deficit in the cell while on the other hand the lower AMP versus ATP concentration represent that the surplus energy i.e. stored

So ACC enzyme could be activated

Therefore the option b is correct

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3 years ago