5) which types have less than 10?
Stand up and suspended.
6) which types have more than 15? Everything except thriller.
7) which months are more than 55? January and February.
January exceeds 55 by 1 and Feb exceeds 55 by 2. $0.25 for each excess. Total charge: $0.75
One way is by using the same number
The equation of the line is given as
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A straight line equation is given in the form

where
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is the gradient and

is the y-interest.
We need to rearrange
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to make

the subject.
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⇒ from here we can read the gradient and the y-intercept. The gradient,

and

.
<span>A line that is parallel to

will have the same gradient,
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but different y-intercept. One example of equation of a line that is parallel to

is

</span>
Answer:
they purchased 40 tickets
Step-by-step explanation:
they already spent 10 to get in the fair and 0.25 × 40 = 10 so 10 +10 =20
The first thing we must do for this case is to observe the value of the y coordinate for a given value of the x coordinate.
We have then:
f (x) = - 4: occurs when x = 0
On the other hand, for x = 2 we have:
f (2) = - 2
Answer:
f (x) = - 4: occurs when x = 0
f (2) = - 2