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aalyn [17]
3 years ago
5

a model of a car is available in 4 colors (black blue silver and white.) and 3 body styles(coupe sedan and wagon) there are also

2 engines to choose from , (16 cylinders, called V6 and four cylinder called l4) what is the probability of choosing a vehicle that is V6 sedan ? (NEED THIS FAST PLEASE HELP:(
Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

the probability of choosing a vehicle with v6 is 1/9

Step-by-step explanation:

favourable cases n(E)=1

exhaustive no. of cases n(S)= 9

now,

probability p(E)=n(E)/n(S)

=1/9

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Which correctly explains how to estimate 33 percent of 87
dedylja [7]

Answer:

Round 33 percent to 30 percent and 87 to 90. Think of 30 percent as 10 percent + 10 percent + 10 percent. Find 10 percent of 90 as 9. So, 30 percent of 90 is 9 + 9 + 9, which is 27.

Step-by-step explanation:

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8 0
3 years ago
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Plz I need help’mmmmmmmm
Anna007 [38]

Answer:

Therefore,

C=\pi d\\C\approx 3.14 \times d\\C\approx 43.96\ inches

Step-by-step explanation:

Let Assume Some Diameter of a Circle, to Solve it

Diameter = d = 14 inch ( say )

C =Circumference

Pi =constant = 3.14

To Find:

C = ?

Solution:

Formula for Circumference of a Circle is given as

C=\pi d

Where,

C = Circumference

d = Diameter

Now Substitute d = 14 inches we get

C=3.14\times 14\approx 43.96\ inches

This way we can find the circumference for any 'd' i.e Diameter

Therefore,

C\approx 43.96\ inches

6 0
4 years ago
Complete the sentences to describe the function f(x) = 2x^2+16x/16x^3-x the function is discontinus at
wel

Answer:

The answer is "\bold{\frac{2(x+8)}{(4x^2- 1)(4x^2+ 1)}}".

Step-by-step explanation:

\to  f(x) = \frac{2x^2+16x}{16x^3-x}

            = \frac{2x(x+8)}{x(16x^2-1)}\\\\= \frac{2(x+8)}{(16x^2-1)}\\\\= \frac{2(x+8)}{((4x)^2-(1)^2)}\\\\= \frac{2(x+8)}{(4x^2- 1)(4x^2+ 1)}\\\\

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3 years ago
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Anon25 [30]
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3 years ago
| 18 - (-13) | <br><br><br> it’s subtracting integers
Anna35 [415]
Answer: 31

How: If there are two negative signs like this, you would connect them together and make it into a addition sign where you then can add them.
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3 years ago
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