The location of the point that is 3/4 the distance from
First, you want to establish your equations.
L=7W-2
P=60
This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.
60=2(7W-2+W)
Now that we only have 1 variable, we can solve.
First, distribute the 2.
60=14W-4+2W
Next, combine like terms.
60=16W-4
Then, add four to both sides.
64=16W
Lastly, divide both sides by 16
W=4
To find the length, we plug in our width.
7W-2
7(4)-2
28-2
L=26
Answer:
His weight is 9/10 of what it used to be before.
Step-by-step explanation:
Answer:
x = 41/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
7(1x - 3) = 4(x + 5)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Simplify: 7(x - 3) = 4(x + 5)
- Distribute: 7x - 21 = 4x + 20
- Subtract 4x on both sides: 3x - 21 = 20
- Add 21 on both sides: 3x = 41
- Divide 3 on both sides: x = 41/3
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 7(1(41/3) - 3) = 4(41/3 + 5)
- Multiply: 7(41/3 - 3) = 4(41/3 + 5)
- Subtract/Add: 7(32/3) = 4(56/3)
- Multiply: 224/3 = 224/3
Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.
And we have our final answer!