50% or 0.5 is the probability that the offspring will have a cleft chin.
Explanation:
Data given:
Cleft chin = dominant, genotype CC
one parent, heterozygous so genotype, Cc
other parent = no cleft chin, genotype is cc (recessive)
probability of child with cleft chin =?
The cross between the given genotype will be shown in punnet square:
C c
c Cc cc
c Cc cc
The results obtained from the cross shows that 50% chances of the progeny having cleft chin.
The phenotype ratio: cleft chin: no cleft chin
1:1
the genotype ratio of the progeny
heterozygous dominant : recessive homozygous
1:1
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The answer to the given question (though the question isn't given), I can assume this is the same as a previous one as the answer is C.
Hope this helped!
