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3 years ago

Write an equation in slope intercept form for a line that passes through the point (1,6) and a slope of 2

Mathematics

1 answer:

denis23 [38]3 years ago

3 0

Answer:

The answer is

Step-by-step explanation:

To find an equation of a line when given the slope and a point we use the formula

$y - y_1 = m(x - x_1) \\$

where

m is the slope

( x1 , y1) is the point

From the question the point is (1,6) and slope 2

The equation of the line is

$y - 6 = 2(x - 1) \\ y - 6 = 2x - 2 \\ y = 2x - 2 + 6$

We have the final answer as

Hope this helps you

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5 1/2 by 4 3/4 by 1/4 scale it down by 1/10

TiliK225 [7]

Answer:

(11/20 by 19/40 by 1/40) OR (0.55 by 0.475 by 0.025)

Step-by-step explanation:

To scale down a set of measurements, simply multiply the original measurement by the factors you're scaling it by. For example, take the first measurement of 5 1/2. To scale this down, I turned the value into an improper fraction (11/2) to make the multiplication process easier. Then, I multiplied 11/2 by the factor of 1/10.

After that, I got 11/20, which is the new first measurement.

7 0

3 years ago

Here is a triangular pyramid and its net.

bazaltina [42]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

3 0

3 years ago

What is m∠PTQ???????????

anyanavicka [17]

Answer:

m∠PTQ = 40°

Step-by-step explanation:

From the picture attached,

Two lines PS and RQ are intersecting each other at a point T.

Vertical angles formed at the point of intersection T will be equal in measure.

m∠PTQ = m∠STR and m∠PTR = m∠QTS

Therefore, (x + 28)° = (2x + 16)°

28 - 16 = 2x - x

12 = x

m∠PTQ = (x + 28)°

= 12 + 28

= 40°

Therefore, measure of angle PTQ is 40°.

5 0

4 years ago

Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)

JulsSmile [24]

Let the given complex number

z = x + ix = $\dfrac{5-i}{3+2i}$

We have to find the standard form of complex number.

Solution:

∴ x + iy = $\dfrac{5-i}{3+2i}$

Rationalising numerator part of complex number, we get

x + iy = $\dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}$

⇒ x + iy = $\dfrac{(5-i)(3-2i)}{3^2-(2i)^2}$

Using the algebraic identity:

(a + b)(a - b) = $a^{2}$ - $b^{2}$

⇒ x + iy = $\dfrac{15-10i-3i+2i^2}{9-4i^2}$

⇒ x + iy = $\dfrac{15-13i+2(-1)}{9-4(-1)}$ [ ∵ $i^{2} =-1$ ]

⇒ x + iy = $\dfrac{15-2-13i}{9+4}$

⇒ x + iy = $\dfrac{13-13i}{13}$

⇒ x + iy = $\dfrac{13(1-i)}{13}$

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0

3 years ago

: 11 = 1 /3 : 6<br><br> plz help

GenaCL600 [577]

<h3>Let the number be x</h3>

$x:11 = \frac{1}{3} :6$

Divide the numbers

$\frac{x}{11} = \frac{ \frac{1}{3} }{6} \\ \frac{x}{11} = \frac{1}{18}$

Multiply all terms by the same value to eliminate fraction denominators

$11 \times \frac{x}{11} = 11 \times \frac{1}{18}$

Cancel multiplied terms that are in the denominator

$x = 11 \times \frac{1}{18}$

Multiply the numbers

$x = \frac{11}{18}$

<h2>Solved ✔︎</h2>

3 0

3 years ago

Read 2 more answers