Question

what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Answer 1

Answer:

$8\frac{1}{8}$

Step-by-step explanation:

The sides of the triangle are $2 \frac{1}{8} \:\text{feet}$ , $3 \frac{1}{2} \:\text{feet}$, and $2 \frac{1}{2} \:\text{feet}$

We need to find the distance around a triangle, so we have to add all the three sides.

So, the distance around a triangle is $2 \frac{1}{8}+3 \frac{1}{2}+2 \frac{1}{2}$

$=2+3+2+\frac{1}{8} +\frac{1}{2} +\frac{1}{2}$

$=7+1+\frac{1}{8}$

$=8+\frac{1}{8}$

$=8\frac{1}{8}$ feet

Hence, the distance around a triangle that has sides measuring $2 \frac{1}{8} \:\text{feet}$ , $3 \frac{1}{2} \:\text{feet}$, and $2 \frac{1}{2} \:\text{feet}$ is $8\frac{1}{8}$ feet.

Answer 2

7 and 1/8. all you need to do is add these together by getting a common denominator of eight

Answer 3

The answer is 8 1/8