Answer:
the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
Step-by-step explanation:
We are given the following information:
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in 

Thus, we are given the time interval [0,12] for t.
- We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
- The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.
First, we differentiate C(t) with respect to t, to get,

Equating the first derivative to zero, we get,

Solving, we get,

At t = 0

At t = 2

At t = 12

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
Add 7 to both sides
3x + 12 = 7x
Subtract 3x
12 = 4x
Divide by 4
x = 3
Answer:
The average rate of change of the function over the interval is 5.
Step-by-step explanation:
Average rate of change of a function:
The average rate of change of a function f(x) over an interval [a,b] is given by:

Interval -3 less-than-or-equal-to x less-than-or-equal-to 3
This means that 

So


Average rate of change

The average rate of change of the function over the interval is 5.
Answer:
260 gallons
Step-by-step explanation:
An estimate of 26.5% of the water used each day is for cleaning and a family uses 68.9 gallons of water a day for cleaning,
Percentage of water used for cleaning= 26.5%
Gallons of water used for cleaning= 68.9
Let the number of gallons used everyday be represented by g. This will give:
26.5% of g = 68.9
26.5/100 × g = 68.9
0.265 × g = 68.9
0.265g = 68.9
Divide both side by 0.265
0.265g/0.265 = 68.9/0.265
g= 260
260 gallons of water are used everyday
300 represents the initial value or the value that you started with.
1.15 is the rate that the function increases by over t (time)