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3 years ago

Two and six hundred thousandths in standard form

Mathematics

2 answers:

loris [4]3 years ago

6 0

2.60,000 that is two AND 6 hundreds in standard form

mihalych1998 [28]3 years ago

3 0

2.600 in standard form

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What is the radian measure of an angle equal to 225 ?

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3 years ago

Lisa purchased a concert ticket on a web site. The original price of the ticket was $75. She used a coupon code to received a 20

Lelu [443]

<h3>Answer:</h3>

12%

<h3>Step-by-step explanation:</h3>

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3 years ago

What is 2 2/3 4/5 and why?

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3 years ago

Question 9

Wittaler [7]

Answer:

Part A) Barbaroid will be executed

Part B) 75 more globin soldiers

Step-by-step explanation:

The army sizes of ORC leaders are

normally distributed with a mean of 5600 goblin soldiers and a standard deviation of 750 goblin soldiers.

The rule is that, if an Orc Leader shows up with an army of a z-score lower than

-1.5, he is immediately executed.

We want to determine whether Lord Barbaroid, an Orc Leader, who appears with an army of 4400 goblin soldiers,

based on the Orc Rule, will he be executed or not.

We find the z-score corresponding to 4400 using

$z = \frac{x - \mu}{ \sigma}$

We substitute x=4400 , the standard deviation and the mean to get:

$z = \frac{4400 - 5600}{750} = - 1.6$

Since Lord Barbaroid's z-score , -1.6 is less than -1.5 he will be executed.

Part B)

We want to find how many more goblin soldiers Lord Barbaroid have needed in order to NOT be executed and meet that Z-Score.

So we need to find the number of globin soldiers that corresponds to -1.5.

$- 1.5 = \frac{x - 5600}{750}$

$750 \times - 1.5 = x - 5600$

$- 1125 = x - 5600 \\ x = 5600 - 1125$

$x = 4475$

Therefore Barbaroid needed 4475-4400=75 more globin soldiers.

4 0

3 years ago