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OlgaM077 [116]
2 years ago
8

Help plsss

Mathematics
1 answer:
andrew11 [14]2 years ago
8 0

(b) is the answer.

Step-by-step explanation:

By the Pythagorean Theorem,

A² + B² = C²

Where:

A = Length of side 1

B = Length of side 2

C = Hypotenuse

This rule applies to all right-angled triangles.

The length of the hypotenuse of a right-angled triangle is always the largest value.

Therefore, we can test the answers with the equation above.

(a)

8² + 18² = 20²

64 + 324 = 400

388 ≠ 400

The rule of Pythagorean theorem doesn't work on a, so (a) is not a right-angled triangle.

(b)

12² + 35² = 37²

144 + 1225 = 1369

1369 = 1369

The rule of Pythagorean theorem works here, so (b) is a right-angled triangle.

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alexandr402 [8]

Answer:

17 green frogs

Step-by-step explanation:

You need to multiply the decimal form of 20% by 85.

To find the decimal form of a percent you take the decimal (20.00) and move it twice to the left (20.00 ---> .2000)

Now, multiply by .2 by 85

(.2)(85) = 17

Therefore, 17 frogs in the pond of 85 frogs are green

<em>Hope this helps!!</em>

<em>- Kay :)</em>

4 0
3 years ago
Heyy it would be really appreciated if you could help !
wolverine [178]

Answer:

x = z/(6πy)

Step-by-step explanation:

Divide by the coefficient of x.

z/(6πy) = 6πxy/(6πy)

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8 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

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so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
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Answer:

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