Answer:
6 seconds
Step-by-step explanation:
<u><em>The question in English is</em></u>
An object is thrown from a platform.
Its height (in meters), x seconds after launch, is modeled by:
h(x)=-5x^2+20x+60
How many seconds after the launch does the object reach the ground?
Let
x ----> the time in seconds
h(x) ---> the height of the object
we have
we know that
When the object hit the ground the height is equal to zero
so
For h(x)=0
we have
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
The solution is x=6 sec
The he object reach the ground at x=6 seconds
5/20 .
add up the number of all the balls combined
5 out of the 20 total are brown
So, first, to make things easier, you should convert these mixed fractions into improper fractions so it's easier to deal with later. The improper fractions will be 51/10 divided by 32/5.
Since you're are dividing fractions, there is a rule when dividing fractions, you have to multiply the number by the reciprocal, meaning the second fraction needs to be flipped and the divide signs will turn into a multiply sign. It will be:
51/10 times 5/32
This is the time where you simply where you can:
51/2 times 1/32
After simplifying, you times the numerator together (the top number of the fraction) and the denominator (the bottom number of the fraction).
=51/64
I can’t see nothing it to white don’t let me Click
105
Bc u divide 42% (0.42) x 250
