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SashulF [63]
3 years ago
7

What is (2-7x)+34-6-(758+8)

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Step-by-step explanation:

2- 7x + 34 - 6-(766)

2-7x + 34 - 6 - 766

2 - 7x - 738

-7x - 736

-(7x + 736

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3 years ago
Plzzzzzz help I don’t understand I know what to do I need to use PEMDAS but my answer is still wrong
Effectus [21]

simplify exponent: 20*(9-4)/50

simplify parentheses: 20*5/50

multiply: 100/50

divide: 2

6 0
3 years ago
What is the answer to 2×[4×(2+1)×3] And how did you get it
ira [324]
Answer is 72

Step by step

Using order of math rules of PEMDAS, we do the inner parentheses “P” first, working outwards with parentheses and then exponents, multiply and divide, add and subtract.

2x [4x(2+1)x3] add inner parentheses

2 x [4 x 3 x 3] multiply inside brackets

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3 0
1 year ago
A randomized trial tested the effectiveness of diets on adults. Among 36 subjects using Diet 1, the mean weight loss after a yea
seropon [69]

Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

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2 years ago
Find the slope of the line above
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3 years ago
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