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3 years ago

Can someone factor this problem for me?

Mathematics

2 answers:

Likurg_2 [28]3 years ago

8 0

Your factored answer will be

(3x-4y) (x-5y)

hope this helps

lesya [120]3 years ago

4 0

3x² - 19xy + 20y² =
3x² - 4xy - 15xy + 20y² =
x(3x-4y) - 5y(3x-4y) =
(3x-4y)(x-5y)

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Can someone help me with this ASAP?! Please and thank you!!

tamaranim1 [39]

Answer:

the 1st answer is correct

Step-by-step explanation:

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3 years ago

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Arte-miy333 [17]

The last bottom problem

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3 years ago

I need 3 questions answered please.

kakasveta [241]

Answer:

$3) \: \: 113 {ft}^{2}$

$4) \: false$

$5) \: 70 {ft}^{2}$

Step-by-step explanation:

3) Area of a circle is

$\pi \times {r}^{2}$

Where r = 6

Thus,

$area = \frac{22}{7} \times {6}^{2}$

$area = \frac{22}{7} \times 36$

$area = 3.143 \times 36$

$area = 113 {ft}^{2} \: (nearest \: whole \: number)$

4) False

Area of a circle is measured by the formula below:

$area = \pi \times {r}^{2}$

5) The formula for calculating the area of a rectangle is given thus:

$area \: of \: a \: rectangle = l \times w$

Where, l = 10ft; w = 7ft

$area = 10ft \times 7ft = 70 {ft}^{2}$

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3 years ago

In a race, a bicyclist travels 3/4 of a mile in 1/4 hour. Determine the unit rate for the speed in miles per hour.

Roman55 [17]

In a race, a bicyclist travels 3/4 of a mile in 1/4 hour. Determine the unit rate for the speed in miles per hour.

5/2 miles per hour

(3/4÷1/4)=3 miles per hour☆☆☆☆☆☆☆

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3 years ago

A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$

As width can never be in negative, $x= 4\ cm$

By substituting the value:-

Width = $x\ cm$ = 4 cm

Thus, width of the box is 4 cm.

4 0

3 years ago