Help pls

Mathematics

1 answer:

Serga [27]3 years ago

6 0

Answer:

x=0 and y=5

Step-by-step explanation:

8x-25+2x=-25

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Is the point (-1,5) a solution to the equation y=2x-4?

lyudmila [28]

No because if you plug in -1 for x and 5 for y 5 doesn’t equal -6. You just plug in the point as x and y and if the equation is true then the point is a solution.

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4 years ago

What is the length of segment AB?<br> answer choices are...<br> 10<br> 12<br> 13<br> 15

gogolik [260]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find the sum of these polynomials.

Lady bird [3.3K]

=(x^8 - x + 7) + (9x^8 + 6)
Combine like terms
=(x^8+9x^8)-x+(7+6)
=10x^8-x+13

D) 10x^8-x+13 is the answer.

Hope this helps! :)

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3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 – 5t2, where t is the tim

Leno4ka [110]

<h2>Time Interval : 1 sec to 1.414 sec</h2>

Step-by-step explanation:

The height of the stuntperson jumping off a $20\text{ }m$ is modelled as $h\text{ }=\text{ }20\text{ }-\text{ }5t^{2}$ . Here $t$ is the time in seconds.

We have to record the person when he is between the heights $15\text{ }m\text{ and }10\text{ }m$ from the ground.

When $h\text{ }=\text{ }15$ ,

$15\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }5\\t^{2}\text{ }=\text{ }1\\t\text{ }=\text{ }1\text{ }sec$

When $h\text{ }=\text{ }10$ ,

$10\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }10\\t^{2}\text{ }=\text{ }2\\t\text{ }=\text{ }\sqrt{2}\text{ }=\text{ }1.414\text{ }sec$

The stuntperson is at height $15\text{ }m$ at $t\text{ }=\text{ }1\text{ }sec$ , and is at height $10\text{ }m$ at $t\text{ }=\text{ }1.414\text{ }sec$ .