I thinks it C, this a difficult question but idk, that my closest guess...
Answer:
k = -6/35
Step-by-step explanation:
To make the function continuous
kx^2 = x+k
These must be equal where the function is defined for two different intervals
This is at the point x=-6 so let x=-6
k(-6)^2 = -6+k
36k = -6+k
Subtract k from each side
36k-k = -6+k-k
35k = -6
Divide by 35
35k/35 = -6/35
k = -6/35
Answer:
33/100
Step-by-step explanation:
I am not so sure, I calculated the percentage and tried converting it to a fraction this is what I got, :)
The only value of p for which the equation has exactly 1 real number solution is p=0.
If p<0, there are no real number solutions and if p>0, there are 2 real number solutions.
Hope this helps,
Brian
Answer:
-4(8-3x)>or =6x-8
Step-by-step explanation:
open d bracket
-32+12x >or = 6x-8
collect like terms
12x-6x >or =-8+32
6x = 24
divide both sides by 6
x= 4