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Mandarinka [93]
3 years ago
6

Create a scenario that leads to an inequality of the form ax + b > c. You can use any of the inequality symbols (>, ≥, &lt

;, ≤) in your inequality. For this step, just write the word problem. Write the inequality and show all work to solve the inequality. Graph the solution to your inequality on a number line. Explain what your solution means in the context of the problem.
Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

5x +3y>-15

5(0)+3(0)

0+0=   0 > -15

Step by step explanation

We have to create a scenario that leads to an inequality of the form ax + b > c.

Word problem: A family went to an park. Entry fee of the park for a family is $20 and the cost of a ride is $10 per person. The family spent more than $100 on that ride.

The required inequality is

Subtract 20 from both sides.

Divide both sides by 10.

It means the number of rides must be greater than 8.

Ann [662]3 years ago
6 0

Answer:

5x +3y>-15

5(0)+3(0)

0+0=   0 > -15

Step by step explanation

We have to create a scenario that leads to an inequality of the form ax + b > c.

Word problem: A family went to an park. Entry fee of the park for a family is $20 and the cost of a ride is $10 per person. The family spent more than $100 on that ride.

The required inequality is

Subtract 20 from both sides.

Divide both sides by 10.

It means the number of rides must be greater than 8.

You might be interested in
Which expressions are equivalent when m = 1 and m = 4? 5 m minus 3 and 2 m 5 m 3 m 4 and m 4 2 m 2 m 7 and 3 m minus 3 m 5 m 3 a
emmasim [6.3K]

The expressions that are equivalent when m = 1 and m = 4 is;

Option B: 3m + 4 and m + 4 + 2m

We are given m = 1 and m =4;

A) 5m - 3 and 2m + 5 + m

B) 3m + 4 and m + 4 + 2m

C) 2m + 7 and 3m - 3 + m

D) 5m + 3 and 4m + 2 + 2m

For option B; 3m + 4 and m + 4 + 2m

Let's put m = 1

3(1) + 4 = 7

Also, 1 + 4 + 2(1) = 7

Similarly, let us put 4 for m to get;

3(4) + 4 = 16

Also, 4 + 4 + 2(4) = 16

In both cases, the expressions are equivalent and as such option B is the right one.

Read more about algebra simplifications at; brainly.com/question/4344214

4 0
3 years ago
Read 2 more answers
Independent Practice
aleksklad [387]

Answer:

A.

2 72 square root of 7

Step-by-step explanation:

Combine the fractions by finding a common denominator.

Exact Form:

2

7

Decimal Form:

0.

¯¯¯¯¯¯¯¯¯¯¯¯

285714

Simplify the expression.

Exact Form:

2

√

7

Decimal Form:

5.29150262

…

8 0
3 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
Please help me out I need it done ASAP
irinina [24]
Your answer will be letter c
7 0
3 years ago
Help please
exis [7]

Answer:

You can put this solution on YOUR website! 5X - 20 = 10 * X 5X - 20 = 10X Subtract 5x from each side-20 = 5X Divide each side by 5-4 = X. Let's make sure it works... 20 less than five times a number (-20-20) is equal to the product of ten and that number (10 * -4)

Step-by-step explanation:

8 0
3 years ago
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