Answer
R=6
Step-by-step explanation:
Hope this helps!
In the given question, we have a graph given, and on the basis of that graph, we have to find the interval where the graph is increasing, decreasing or constant .
As we see in the graph, that the graph goes up and up only, no where it goes down or it is constant.
So the graph is increasing on all real numbers and decreasing nowhere.
A(t) = P(1+(r/n))^(nt)
A(3) = 500(1+0.04/1))^(1*3)
A(3) = 500(1.04)^3
A(3) = $562.43
Answer:
4th term = 28
5th term = 37
6th term = 45
Step-by-step explanation:
f(n + 1) = f(n) + 8
f(1) = 5
f(1 + 1) = f(1) + 8 = 5+8 = 13
f(2) = 13
f(2 + 1) = f(2) + 8 = 13+8 = 21
Thus, series is 5, 13, 21......
In arithmetic series
Nth term is given by
n th term = a + (n-1)d
where a is the first term
and d is the common difference.
common difference d = nth term - (n-1)th term
For this series
a = 5
lets take nth term as 2nd term and 1st term as (n-1)th term
d = 13-5 = 8
n th term = a + (n-1)d
using the formula for nth term
4th term = 5 + (4-1)8 = 29
5th term = 5 + (5-1) 8= 37
6th term = 5+ (6-1)8 = 45
Thus, 4th term = 28
5th term = 37
6th term = 45
Note this, problem can be solved using f(n + 1) = f(n) + 8 by putting n = 3,4,5 as well but for learning concept of arithmetic series, i have used above process. Hope it helps.
Answer:
h=3V/πr²
Step-by-step explanation:
