Question

Having trouble.. help?

Answer 1

Answer:

(A) $y = x+3$

Step-by-step explanation:

Using the values of (-6, -3), (3,6), and (5,8) we can substitute the values into each equation and see if the equation meets the requirements for all 3.

Let's test A first.

$-3 = -6+3$

Correct, let's try the second pair.

$6 = 3+3$

Correct, let's try the third pair.

$8 = 5+3$

So yes, this equation works.

For fun, let's try the other equations.

Let's test B.

$-3 = -6-3$

This is not true as -6 -3 = -9. So this equation is immediately ruled out.

Let's test C.

$-3 = 2\cdot-6$

Again this doesn't work, as -6 times 2 is -12. So this equation is also ruled out.

Let's try D.

$-3 = \frac{1}{2}\cdot-6$

This works, as half of -6 is -3 - however the equation will only work if all 3 pairs work for it.

Let's try the second pair.

$6 = \frac{1}{2}\cdot3$

This doesn't work, as half of 3 is 1.5. This equation is also ruled out.

Therefore, A is the only equation that works with these pairs.

Hope this helped!

Answer 2

A. {(x, y): y= x + 3}