Answer:
0.
Step-by-step explanation:
1) y'=(x⁴)'=4x³;
2) ∡ y'=0, ⇒ 4x³=0; ⇒ x=0.
Answer:
(f + g)(2) = 10, (h – g)(2) = –9, (f × h)(2) = –12, (h / g)(2) = –0.5
Step-by-step explanation:
This can be solved in two ways: With heavy tools or with just algebra.
What is your level? Have you studied calculus?
With pure algebra:
We need to find the maximum of the function <span>h = −16t^2 + 36t + 5
Lets take out -1 for simplicity:
</span><span>h = −(16t2 - 36t - 5)
For now lets just work with this: </span>16t^2 - 36t - 5
16t^2=(4t)^2
(4t-x)^2= 16t^2-2*4xt+x^2
we have -36t so x should be 4.5 as 2*4*4.5=36
Lets see what we have now:
16t^2 - 36t - 5= (4t-4.5)^2 is this true? No but close
(4t-4.5)^2= 16t^2- 2*4*4.5t +4.5^2= 16t^2-36t+20.25
16t^2 - 36t - 5 and 16t^2-36t+20.25 nearl the same just take away 25.25 from the right hand side
Getting long, just stay with me:
16t^2 - 36t - 5= (4t-4.5)^2 - 25.25
h= -{(4t-4.5)^2 -25.25}
h=-(4t-4.5)^2 + 25.25
We want to find the maximum of this function. -(4t-4.5)^2 this bit is always negative or 0, so it maximum is when it is 0. Solve: 4t-4.5=0
t=1,125
Step-by-step explanation:
Since 8.7b = (-2.9) * (-3b),
and -11.6 = (-2.9) * (4),
8.7b - 11.6 = -2.9(4 - 3b).
Answer:
Step-by-step explanation:
First we know triangle WXY is an equilateral which means all its angles are 60 degrees.
Next we know triangle WZY is an isosceles so it has 2 angles that are equal to each other.
Since angle Z is an obtuse angle. We can calculate the other angles which we will assume are equal because 138+138 is greater than 180 degrees.
180-138 = 42
42/2 = 21 <-- divide by 2 because we know we're looking for 2 angles
For the angles of WXY.
60-21 = 39
Therefore
Angle I = 60
Angle 2 = 39
Angle 3 = 21
Angle 4 = 39
Angle 5 = 21
