Answer:
z = 74 degrees
y = 115 degrees
Step-by-step explanation:
Explanation in the attachment.
You need to subtract 25 by 18
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Answer:
Teresa should build 7.5 inches model.
Step-by-step explanation:
Consider the provided information.
Teresa is building a scale model of the JP Morgan chase Tower in Houston.
Her scale model, 1.5 inches represents 61 meters.
The actual building is 305 meters tall,
First find how many 61's are there in 305.
For this divide 305 by 61.

Actual building is 5 times taller than 61. Thus the model should be 5 times taller than 1.5.
multiply 1.5 with 5 gives us:

Hence, Teresa should build 7.5 inches model.
Answer:
a) 98.01%
b) 13.53\%
c) 27.06%
Step-by-step explanation:
Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2
If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,
a)
In this case, we are looking for P(0)
So, the probability that a car has no flaws is 98.01%
b)
Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.
Now P(k) is the probability that 10 cars have k flaws and
and
And the probability that 10 cars have no flaws is 13.53%
c)
Here, we are looking for P(1) with P defined as in b)
Hence, the probability that at most one car has no flaws is 27.06%