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Sav [38]
3 years ago
10

Can someone plz help me with this plzzzzz

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

D. m = \sqrt{3}, n = 1

Step-by-step explanation:

The triangle given is a 30-60-90 triangle. This means that the longer side of the leg is x\sqrt{3} (m), the shorter side of the leg is x (n), and the hypotenuse is 2x.

The hypotenuse is already given as 2, and since the hypotenuse is 2x, to find the shorter side (n), just divide by 2, giving you n = 1.

Now onto the longer side (m); it's represented by x\sqrt{3}, and since x is just 1, all you do is put x in front of \sqrt{3}.

But in this case, x is just 1, so it's like "imaginary," and doesn't need to be written out.

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Find the value of each variable.<br> 105°<br> 86°<br> 106°/2°
forsale [732]

Answer:

z = 74 degrees

y = 115 degrees

Step-by-step explanation:

Explanation in the attachment.

5 0
2 years ago
Is it subtracting that I need to do or is it adding?
alisha [4.7K]
You need to subtract 25 by 18
4 0
3 years ago
A car requires 22 litres of petrol to travel a distance of 259.6 km.Find
Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0
3 years ago
Teresa is building a scale model of the JP Morgan chase Tower in Houston.In her scale model, 1.5 inches represents 61 meters. Si
Jet001 [13]

Answer:

Teresa should build 7.5 inches model.

Step-by-step explanation:

Consider the provided information.

Teresa is building a scale model of the JP Morgan chase Tower in Houston.

Her scale model, 1.5 inches represents 61 meters.

The actual building is 305 meters tall,

First find how many 61's are there in 305.

For this divide 305 by 61.

\frac{305}{61}= 5

Actual building is 5 times taller than 61. Thus the model should be 5 times taller than 1.5.

multiply 1.5 with 5 gives us:

1.5\times 5=7.5

Hence, Teresa should build 7.5 inches model.

7 0
3 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
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