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givi [52]
3 years ago
10

The width of a rectangle is 18 meters less than twice the length, x. The width of the rectangle is 68 meters. Which equation can

be used to find the length of the rectangle, x?
A x + 18= 68

B 2x + 18= 68

C 2x - 18 + 68

D 18 - 2x = 68
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

None of the options are correct, as the answer is <u>2x - 18 = 68.</u>

Step-by-step explanation:

The <u>2x</u> represents the length (x) being half of the width (68)

The <u>-18</u> represents the width (68) being 18 less than twice the length (2x)

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7/8 + 4/8= 11/8 so 11/8 ÷2 = 5.5/8 she puts 5 1/2 /8 cups of the mixture in each bowl
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3 years ago
Find the values of x and y in the diagram​ and show work please it's for geometry class
Romashka-Z-Leto [24]

Answer:

x = 10

y = 70

Step-by-step explanation:

By using the vertical angles theorem we know that x+ y +10 = 90, also simplified to x + y = 80

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When you put into the equation 2x + y = 90 you will get 2x -x +80 = 90

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8 0
3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
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4/10  x 0.04 = (of means multiply)
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