The sixth grade has 100 students, there are three home rooms 40 students in one class and 34 in another and the rest are in the
1 answer:
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Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:
a)
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082
b)
The area to the left of z=3.00 is 0.9987
c) The z-value of 1200 is 0
The area to the left of 0 is 0.5
The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is
d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e)
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1
Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:
In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K: