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3 years ago

What type of angles are 1 & 2

Mathematics

1 answer:

Stolb23 [73]3 years ago

8 0

Answer:

Step-by-step explanation:

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What is the greatest common factor of 12x 16x 8x

slega [8]

Answer:

Step-by-step explanation:

The Factors of 12

1,12, 2,6 3,4

1,16 2,8 4,4

1,8 ,2,4

The highest factor they share is 4 so it would be the GCF. Then you would have to add the x back into the GCF

Hope It helped

8 0

3 years ago

Pls tell the answer for 50 points!

White raven [17]

Answer:

7*11^5

Explanation:

(the photo)

5 0

2 years ago

A patient is on a weight loss plan. At the beginning, the patient weighed 279 pounds. The first week, he lost 5.5 pounds. The 2n

Stolb23 [73]

The patient weighs about 268 pounds after the 4 week diet.

6 0

3 years ago

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Can somebody help me with this pretest

Ann [662]

Answer:

yes, I can help you do it.

8 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers