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A naked, male corpse was found at 8AM on Tuesday, July 9.The air temperature wasalready 26.7˚C (81˚F). The body exhibited some s

Slav-nsk [51]

Answer:

x = 9.87 hours ago.

Further explanation is present below.

Explanation:

Data given:

Air Temperature = 26.7°C (81°F)

Body temperature = 34.4°C (93.9°F)

We are given that, Livor mortis was absent. Secondly, The body exhibited some stiffness in the face and eyelids.

So, it can be concluded that, body must have died recently, as Livor mortis was absent plus the presence of stiffness in the face and eyelids. Furthermore,

The normal body temperature = 37°C

Body temperature in our case = 34.4° C

Difference = 37 -34.4 = 2.6°C

And Air temperature = 26.7°C

Which is a very low difference, in addition, it has not acquired the air temperature so, all this evidence certifies that body died recently.

Now, we have to calculate, how recently it died.

Formula:

0.78 . x = difference of body temperature and air temperature

Where, x = number of hours = time required,

0.78 . x = (34.4 - 26.7)

0.78 . x = 7.7

x = 7.7/0.78

x = 9.87 hours ago.

It means that, naked male corpse was died 9.87 hours ago.

Now, we are asked to find out clothing on the body had made a difference or not.

So, Yes it would definitely make a difference. As body would have more warmer than being naked. and it would result in a calculation of a different time of death. (body temperature would have > 34.4°C)

3 0

3 years ago

A force of 100N is applied to an area of 100mm².what is the pressure exerted on the area in N/m².

Dmitry_Shevchenko [17]

Answer:

P = 1000000[Pa] = 1000 [kPa]

Explanation:

To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.

$P=F/A$

where:

P = pressure [Pa] (units of pascals)

F = force = 100 [N]

A = area = 100 [mm²]

But first we must convert the units from square millimeters to square meters.

$A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]$

Now replacing:

$P=100/0.0001\\P=1000000[Pa]$

3 0

3 years ago

. 1. When work is done and a force is transferred which choice describes the movement of the object? (Points : 3). . a) When wor

MissTica

I think that when work is done and a force istransferred an object must move in the direction of the force.

6 0

4 years ago

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A 17.3 eV electron has a 0.295 nm wavelength. If such electrons are passed through a double slit and have their first maximum at

4vir4ik [10]

Answer:

0.541 nm

Explanation:

The condition for maxima is,

$dsin\theta=m\lambda$

Here, m=0,1,2,.....

And d is the slit separation, m is the order of maxima, $\lambda$ is the wavelength.

Given that, the 17.3 eV electron posses a wavelength of

$\lambda=0.295 nm\\\\\lambda=0.295\times 10^{-9}m$

And the order of maxima is $m=1$ .

And the angle at which first order maxima occur is, $\theta=33^{\circ}$ .

Put these values in maxima condition while solving for d.

$d=\frac{1\times 0.295\times 10^{-9}m}{sin33^{\circ}} \\d=\frac{0.295\times 10^{-9}m}{0.545} \\d=0.541\times 10^{-9}m}\\d=0.541 nm$

Therefore, the slit separation is 0.541 nm.

7 0

3 years ago

What are some possible sources of error when using the modified mercalli scale to locate the epicenter of an earthquake?

anygoal [31]

The Modified Mercalli scale is used measures the amount of damage done during an earthquake. This helps to locate the epicenter of the earthquake. It depicts the intensity of the earthquake based on the damage occurred due to the earthquake. The responses from many people who experienced the earthquake are collected by the scientists, assigned a value and plotted on a map

The plotted number can change with the reference place within the region of disturbance. It depends on the location of the observer with reference to the epicenter of the earthquake. The reporting depends on the witness. Some can exaggerate the extent of damage caused. All the above mentioned are possible sources of error when using the Modified Mercalli scale to locate the earthquake's epicenter.

7 0

3 years ago

Read 2 more answers