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3 years ago

Which factors affect heat transfer between a warm and a cool substance?

1 answer:

8 0

Factors that affect heat transfer are:

1) Difference in temperature,
2) Mass of the object
3) Specific heat of the object

Hope this helps!

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A student wanted to check her idea that a planet that is closer to the Sun receives more of the Sun’s energy than a planet that

goblinko [34]

Answer:

C. a clamp light with a 150-W lightbulb placed 25 cm from the radiometer

Explanation:

because the temperature has to be set, meaning it can't change, and it should be a different distance away than the first one.

Hope this helps! Stay safe!

3 0

3 years ago

Read 2 more answers

a 60g tennis ball travelling at 30m/s hi a wall and bounce back at 20m/s.calculate (a)momentum of the ball before impact (b)mome

frez [133]

Explanation:

the formula for momentum is denoted by p=mv where p is momentum, m is mass and v is velocity. thus, the velocity before impact would be 0.060 x 30 = 1.8 kg/ms

the second one would just be 0.060 x 20 0.72kg/ms

I'm not 100 percent sure this is correct but yeah

6 0

3 years ago

A ball is kicked horizontally at 4.6 m/s off of a cliff 13.4 m high. How far from the cliff will it land.

Mekhanik [1.2K]

<h3>Answer:</h3>

7.53 m

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Horizontal Velocity of the Ball = 4.6 m/s

Initial Vertical Velocity of the Ball = 0 m/s

Height from which ball is kicked = 13.4 m

<u>Time taken by the ball to reach the ground:</u>

The ball has an initial vertical velocity of 0 m/s

it also has a downward acceleration of 10 m/s² due to gravity

<u>Solving for the time taken:</u>

s = ut + 1/2(at²) [second equation of motion]

replacing the values

13.4 = (0)(t) + 1/2 (10)(t²)

13.4 = 5t²

t² = 13.4/5 [dividing both sides by 5]

t² = 2.68

t = 1.637 seconds [taking the square root of both sides]

<u>Horizontal distance covered by the ball:</u>

Since there are no horizontal opposing forces on the ball,

the ball will more horizontally at a velocity of 4.6 m/s until it hits the ground

We calculated that the ball will hit the ground in 1.637 seconds

<u>Distance covered:</u>

s = ut + 1/2 (at²) [seconds equation of motion]

s = ut [since a = 0m/s² in the horizontal plane]

replacing the values

s = 4.6 * 1.637

s = 7.53 m

Hence, the ball landed 7.53 m from the cliff

5 0

3 years ago

How do rising temperature affect the process of convection

Papessa [141]

<span>Convection is a process of heat transfer between a surface and a moving fluid. It occurs when the air has a lower temperature than the body, and the body transfers heat through contact with the cold air around it. Air heating causes it to rise. The increase in temperature affects the convection process, since as the warm air rises, the cold air takes its place, thus completing its convection cycle. Example: Wind</span>

4 0

3 years ago

Read 2 more answers

A pump is used to send water through a hose, the diameter of which is 10 times that of the nozzle through which the water exits.

Keith_Richards [23]

Use VFR1 = VFR2 to discover the velocity at in the hose VFR = A * V

D hose =10 * D nozzle, R hose = 5 * D nozzle

Area of a circle = πR^2

Area h=3.14*25*D^2 = 75.5D^2

(Radius=Diameter/2) area n = 3.14*(D^2/4) = .785D^2

Use VFR = VFR v2 = 0.4m/s

0.4*.785D^2 = 75.5*D^2* v1 D^2

= .314 =75.5*V1

v1 = 0.004m/s

Now we have the velocity, we can use Bernoulli's equation.

P1+ρgh1+ρV1^2 /2 = constant

There is no atmospheric pressure before so the P1= the gauge pressure at the pump, let’s call the height of the hose 0m and the height of the nozzle 1m so the is no ρgh1 Likewise, there is only atmospheric pressure at the nozzle which is 100000 PA, and lastly the density ρ of water is 1000 KG/M^3

Pg + 1000*.004^2/2 = 100000+1000*9.8*1+ 1000*0.4^2/2

Pg + .008= 100000+9800+80

Pg+.008= 109880

Pg=109880.008 PA

3 0

3 years ago