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Elina [12.6K]
3 years ago
6

Reconocimiento de suceciones aritmeticas y geometricas

Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

el producto es 4 o 3 por que dice hallar el producto de CUATRO termino estonses 3×4= 12

Step-by-step explanation:

si necesita ayuda o necesita responder sus preguntas en cuestión de segundos o minutos, hágamelo saber y lo ayudaré :)

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Find the surface area of the triangular prism (above) using its net (below).
vovangra [49]

Answer:

96 cm^2 (centimetres squared)

Step-by-step explanation:

(7 x 3) x 2 = 42

6x2 / 2 x 2 = 12

6 x 7 = 42

42 + 12 + 42 = 96 cm^2

3 0
3 years ago
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Solve for<br><br> 2u = 4/9<br><br> Simplify your answer as much as possible.
mafiozo [28]

Answer:

2/9

Step-by-step explanation:

If you meant you want to find U,

1) Divide both side by 2. -> U = 4/9 divided by 2

2) You get U = 4/18, which you can further simplify by dividing 2 on top and bottom to get 2/9

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3 years ago
What is 3.41 ((with 41 repeating at the end)) as a simplified fraction?
Andre45 [30]

<u>3 41/99. </u>

3.4141414...

100x= 341.4141414...

341.414141414...

- 3.41414141414..= 338

99x= 338/99 or 3 44/99

5 0
3 years ago
What is the greatest common factor of 39 and 65 list all the factors
Elina [12.6K]

Answer:

hu

Step-by-step explanation:

hij

6 0
3 years ago
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Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
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