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2 years ago

15

CAN SOMEONE HELP ME ANSWER THIS

1 answer:

yan [13]2 years ago

8 0

<6=<1=75 {Corresponding angles} :-)

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How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

5 0

2 years ago

Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.

Svet_ta [14]

S＝［h(2h/tanθ+w+w）］/2

6 0

2 years ago

I need some help with this, I am supposed to solve for x

liq [111]

They are the same measurements, because:

from 10x + 5, first do vertical angle.

then, alternate interior angle,

then vertical angle again,

and another alternate interior angle.

For each vertical and alternate interior angles, the measurements stay the same.

Set them equal to each other, isolate and solve for x.

10x + 5 = 11x - 1

First, isolate the x. Subtract 10x from both sides, and add 1 to both sides

10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)

Simplify

5 + 1 = 11x - 10x

6 = x

x = 6

6 is your answer for x.

hope this helps

3 0

3 years ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

so

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

2 years ago

at a school carnival , tickets can purchased to participate in different activisties the table shows the total cost for differen

Radda [10]

Answer:

the answer is 4

Step-by-step explanation:

4 0

2 years ago