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Darya [45]
3 years ago
6

I need help on this question

Mathematics
1 answer:
Pavel [41]3 years ago
7 0
I think the answer is D sorry if it’s wrong and good luck
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SQDANCEFAN ECSPECIALLY PLZ HELP ME THX SO MUCH!!! Or anyone else can answer if they know, but if you put stu-pid answers you wil
lesya [120]

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Answer:

  90.1 m

Step-by-step explanation:

The length of the shortcut is the hypotenuse of a right triangle with side lengths 30 and 85. That length can be found using the Pythagorean theorem.

  PQ² = 30² +85² = 8125

  PQ = √8125 ≈ 90.1

The length of the shortcut is 90.1 meters.

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3 years ago
X^2+ 8x+ How to make it a perfect square
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Madelyn has x nickels and y dimes, having a maximum of 15 coins worth no
aliina [53]

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Answer:

 2 nickels, 9 dimes

Step-by-step explanation:

When there are a number of overlapping shaded areas on the graph, I find it convenient to use the reverse of the inequalities. That makes the <em>unshaded</em> area the solution space. Here, the vertices of the triangular solution space are ...

  (2, 9), (2, 13), (6, 9)

Any of the grid points within (or on) this triangle is a possible solution. One of them is (2, 9) corresponding to 2 nickels and 9 dimes.

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Three solutions are shown:

  (x, y) = (2, 9), (3, 10), (4, 11)

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3 years ago
What is the y in 10.3=0.6y
ollegr [7]
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6 0
3 years ago
The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op
andreev551 [17]

<u>B) </u>x   =4.28

<u>C) </u> volume =  135.25cm^3 .

<u>Step-by-step explanation:</u>

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = length(width)

⇒ Area = length(width)

Putting values according to question we get :

⇒ 58 = (2x+5)(x)

⇒ 58 = (2x^2+5x)

⇒  2x^2+5x - 58 = 0

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒  2x^2+5x - 58 = 0

By quadratic formula

⇒ x   = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x   = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}

⇒ x   = \frac{-5 \pm 22.11}{4}

⇒ x   = \frac{-5 + 22.11}{4} , x   = \frac{-5 - 22.11}{4}    { Since side can't be negative ! }

⇒ x   =4.28

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28

We know that volume is given by :

⇒ length(width)(height)

⇒ 13.86(4.28)(2.28)

⇒ 135.25cm^3

Therefore , volume =  135.25cm^3 .

7 0
3 years ago
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