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4 years ago

Which value is the solution for this equation?

2 answers:

6 0

The answer is 6
Because you add 15 to both sides of the equation and 27+15 is 42. So the your equation looks like 7y= 42 and then divided by 7 on each side witch canceled out the 7/7 so then you have 7/42 witch is 6

boyakko [2]4 years ago

3 0

The anwser is y = 6 or c

You might be interested in

To change a recipe that serves 8 to make it serve 5, by what fraction would you multiply each ingredient?

NARA [144]

Let, that fraction = x
So, 8 * x = 5
x = 5/8

In short, Your Answer would be 5/8

Hope this helps!

8 0

4 years ago

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

4 years ago

Help please ASAP!!!!!<br> you can zoom in to see better

meriva

Answer:

true, false, and false

Step-by-step explanation:

6 0

3 years ago

Suppose that the relation S is defined as follows.S = ( -6,0), (5,-3), (-6,-1), (-8,5)Give the domain and range of S. Write your

Angelina_Jolie [31]

The domain of a relation is all the x - values the relation can take, so:

domain = {-8, -6, 5}

The range, in addition, is all the y - values the relation can take, so:

range = {-3, -1, 0, 5}

3 0

1 year ago

Often sales of a new product grow rapidly at first and then level off with time. This is the case with the sales represented by

True [87]

Answer:

Here we have the function:

S(t) = 500 - 400*t^(-1)

Then the rate of change at the value t, will be:

S'(t) = dS(t)/dt

This differentiation will be:

S'(t) = -400/t^2

Then:

a) the rate of change at t = 1 is:

S'(1) = -400/1^2 = -400

The rate of change after one year is -400

b) t = 10

S'(10) = -400/10^2 = -400/100 = -4

The rate of change after 10 years is -4, it reduced as the years passed, as expected.

7 0

3 years ago