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3 years ago

8qх + 21ру + брx + 28qy

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

5 0

Answer:

What's the question? equals?

Step-by-step explanation:

8qх + 21ру + брx + 28qy

8qх + 28qy + брx + 21ру rearranged the terms to help factoring

4q(2x + 7y) + 3p(2x + 7y)

(2x + 7y)(4q + 3p) or (4q + 3p)(2x + 7y)

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A circle is centered at the point (-7, -1) and passes through the point (8, 7).The radius of the circle is____ units. The point

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Part 1) The radius of the circle is r=17 units

Part 2) The points (-15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

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substitute

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step 2

Find out the y-coordinate of point (-15,y)

The equation of the circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute the values

$(x+7)^2+(y+1)^2=17^2$

$(x+7)^2+(y+1)^2=289$

Substitute the value of x=-15 in the equation

$(-15+7)^2+(y+1)^2=289$

$64+(y+1)^2=289$

$(y+1)^2=289-64$

$(y+1)^2=225$

square root both sides

$(y+1)=(+/-)15$

$y=-1(+/-)15$

$y=-1(+)15=14$

$y=-1(-)15=-16$

therefore

we have two solutions

point (-15,14) and point (-15,-16)

see the attached figure to better understand the problem

8 0

3 years ago

8qх + 21ру + брx + 28qy​

8qх + 21ру + брx + 28qy