Answer:
7/3
Step-by-step explanation:
Simplify the following:
(1 + 3/4) (1 + 1/3)
Hint: | Put the fractions in 1 + 1/3 over a common denominator.
Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:
(1 + 3/4) 3/3 + 1/3
Hint: | Add the fractions over a common denominator to a single fraction.
3/3 + 1/3 = (3 + 1)/3:
(1 + 3/4) (3 + 1)/3
Hint: | Evaluate 3 + 1.
3 + 1 = 4:
(1 + 3/4)×4/3
Hint: | Put the fractions in 1 + 3/4 over a common denominator.
Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:
4/3 4/4 + 3/4
Hint: | Add the fractions over a common denominator to a single fraction.
4/4 + 3/4 = (4 + 3)/4:
4/3 (4 + 3)/4
Hint: | Evaluate 4 + 3.
4 + 3 = 7:
7/4×4/3
Hint: | Express 7/4×4/3 as a single fraction.
7/4×4/3 = (7×4)/(4×3):
(7×4)/(4×3)
Hint: | Cancel common terms in the numerator and denominator of (7×4)/(4×3).
(7×4)/(4×3) = 4/4×7/3 = 7/3:
Answer: 7/3
Answer:well you need to know the actual height and diameter of the container if it's a curved shape
Step-by-step explanation:
Turning a car on and off, turning the oven on and off
The solution set of -4(x + 3) ≤ -21 is x ≥ 2.25
<h3>How to graph the solution set?</h3>
The inequality is given as:
-4(x + 3) ≤ -21
Divide both sides by -4
x + 3 ≥ 5.25
Subtract 3 from both sides
x ≥ 2.25
This means that the solution set of -4(x + 3) ≤ -21 is x ≥ 2.25
See attachment for the number line
Read more about inequality at:
brainly.com/question/25275758
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Total light bulbs = 24
Defective bulbs = 2
Non defective bulbs = 22
The probability of selecting 10 bulbs with two defective bulbs
We will use combination formula which states:
= 
= 
= 
= 0.16
Therefore, the probability that both defective bulbs will be selected is 0.16
