Answer:
<em>2(x - 1) - 1 = 3(x + 1) - 6 - x</em>
<em>There are infinitely many solutions.</em>
Step-by-step explanation:
<u>Equations</u>
Suppose Nicky was trying to solve the equation
2(x - 1) - 1 = 3(x + 1) - 6 - x
Operating:
2x - 2 - 1 = 3x + 3 - 6 - x
2x - 3 = 2x - 3
Subtracting 2x:
-3 = -3
This equation is true regardless of the value of x, thus x can have any value. There are infinitely many solutions.
The same result could have come with these equations:
4x - 3 = -3 + 4x
4(x - 1) + 1 = 4(x + 1) - 7
i think you just have to do 3 + 14+2+2+3and then solve i guess
Answer:
Below
Step-by-step explanation:
● f(x) = -2x + 3
● f (0) = -2 (0) +3 = 3
● f(-32) = -2(-32)+3 = 64 + 3 = 67
● f(10) = -2(10) +3 = -20 + 3 = -17
● f(-17) = -2(-17) + 3 = 34 + 3 = 37
● f(10) => -17
● f(-17) => 37
I don't know what the backtracking method is, sorry.
3(x + 2) = 5x
3x + 6 = 5x
6 = 5x - 3x = 2x
x = 6/2 = 3
Answer:
$41.11
Step-by-step explanation:
28.75 + (28.75 x 0.35) + (28.75 x 0.08)
Please mark brainliest and have a nice day
Full answer is 41.1125
