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SashulF [63]
3 years ago
11

Refer to the following conditional statement:

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0
The answer is B, I'm sure of it
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Factorise the following questions
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ii)

\sqrt{2} x^{2}  + 3x +  \sqrt{2}   \\  =  \sqrt{2}x(x +  \sqrt{2} ) + x +  \sqrt{2} \\  = ( \sqrt{2} x + 1)(x +  \sqrt{2} )

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3 years ago
Evaluate 3x^2 +2x-5 when x=4
Daniel [21]
Replace each "x" in the original equation with (4):

  3(4)^2 + 2(4) - 5
= 3(16)  + 8 - 5         =        48 + 8 - 5.  Can you finish this?
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3 years ago
Solve for z.<br> Z&lt;-9<br> Z&gt;-9
Alex73 [517]

Answer:

z>-9

Step-by-step explanation:

3 0
3 years ago
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A bag of trail mix weighs 2 lb. By weight, 20% of the bag is oats. How many pounds is the oats portion of the trail mix? (a) Wri
posledela
Answer: 0.4 pounds of the trail mix is oats.

To find the answer, you can set up a proportion. We can use the percent proportion below.

part/whole = percent/100

x/2 = 20/100

To solve this you cross multiply and divide.

100x = 40
x = 0.4
3 0
4 years ago
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
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