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Ludmilka [50]
3 years ago
6

Eddie plotted his house on a coordinate plane, along with a few landmarks from his neighborhood.

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

library

Step-by-step explanation:

Alekssandra [29.7K]3 years ago
4 0

Answer:

library

Step-by-step explanation:

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Karonlina flips a coin 60 times. how many times would you expect it's to land heads up?
Novosadov [1.4K]

Answer:

30 times

Step-by-step explanation:

There's a 50% chance that they will get heads.

60 divided by 2 is 30

50% of 60 is 30

7 0
3 years ago
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Identify the parent function. 5 --5<br>a absolute <br>b reciprocal<br>c cube root<br>d square root​
velikii [3]

Step-by-step explanation:

For an absolute value function, the graph will look like an arrow with a sharp inflection point.

Reciprocal function will tend towards a limit when stretched to infinity.

Cube root and square root functions do not tend towards infinity at x = 0, because it is either 0 or the constant value.

The best answer here is Reciprocal. (B)

5 0
3 years ago
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Please answer this, I need help ​
frutty [35]

Answer:

-$7

Step-by-step explanation:

20 - 15 = 5

5 + 5 = 10

10 - 10 = 0

0 - 7 = -7

8 0
3 years ago
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A person can see the top of a building at an angle of 65°. The person is standing 50 ft away from
zhannawk [14.2K]

9514 1404 393

Answer:

  (b)  112.2 ft

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

For the given geometry, this becomes ...

  tan(65°) = (height above eye level)/(50 ft)

Then we have ...

  (height above eye level) = (50 ft)tan(65°) = 107.2 ft

Adding the height of eye level will give us the height of the building.

  building height = (eye level height) + (height above eye level)

  building height = (5 ft) + (107.2 ft)

  building height = 112.2 ft

6 0
2 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
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