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3 years ago

Eddie plotted his house on a coordinate plane, along with a few landmarks from his neighborhood.

Mathematics

2 answers:

bulgar [2K]3 years ago

7 0

Answer:

library

Step-by-step explanation:

Alekssandra [29.7K]3 years ago

4 0

Answer:

library

Step-by-step explanation:

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Klio2033 [76]

Answer:

A. 36

Step-by-step explanation:

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3 years ago

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Help me with quistion 1 and 2

Anit [1.1K]

The answer to number 1 is B

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3 years ago

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Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview

mario62 [17]

Answer: The required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.$

So, the general solution of the given equation is

$y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.$

According to the given conditions, we have

$y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

and

$y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.$

From equation (ii), we get

$B=\dfrac{7}{3}.$

Thus, the required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

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2 years ago

Answer part A, B and part C correctly please.

Radda [10]

Answer:

Part A:

C= cash Sue earns

H = hours Sue works

C is dependent upon H because C only changes when H is changed.

Part B:

(0,0)

(1,6)

Part C:

C=6H

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3 years ago

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(10)(11) Geometry Check Ans 10) 5 11) x = 33 y = 38 z = 109

ICE Princess25 [194]

Problem 10

You are correct. You divide 360 over the exterior angle measure to get 360/72 = 5

=========================================================

Problem 11

x = 33 is correct as this angle is an alternate interior angle pair with the 33 degree angle up top

y = 38 is correct since y+33+109 = 180 solves to y = 38. In other words: 38+33+109 = 180

z = 109 is correct. The opposite angles of a parallelogram are congruent

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3 years ago