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zepelin [54]
3 years ago
13

13. The numerator of a rational number is 3 less than the denominator. If the denominator is

Mathematics
1 answer:
g100num [7]3 years ago
5 0

Fraction = 4/7

Step by step Explanation

Let the denominator be x.

Numerator = 3 less than denominator

denominator = x

Numerator = (x – 3)

Now, Adding 5 to denominator

adding 2 to numerator.

Numerator = (x – 3 + 2)

Denominator = (x + 5)

(x – 3 + 2)/(x + 5)

According to the question

 (x – 3 + 2)/(x + 5) = 1/2

(x – 1)/(x + 5) = 1/2

2(x – 1) = 1(x + 5)

2x – 2 = x + 5

2x – x = 5 + 2

x = 7

So,

=> Denominator x = 7

=> Numerator (x – 3) => (7 – 3) = 4

= > Fraction = 4/7

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GenaCL600 [577]

The measure of angle ABC is 45°

<em><u>Explanation</u></em>

Vertices of the triangle are:   A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) =\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5

Length of the side AC (b) = \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}

Length of the side AB (c) = \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}

We need to find ∠ABC or ∠B . So using <u>Cosine rule</u>, we will get...

cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree

So, the measure of angle ABC is 45°

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Step-by-step explanation:

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3 years ago
7 divided by 4 x + 3 Y + 4 divided / 4 x minus 3 Y is equal to 5 / 4
DerKrebs [107]

9514 1404 393

Answer:

  (x, y) = (4, 4)

Step-by-step explanation:

If you attempt to solve this by clearing fractions, you end up with an extraneous solution. Here, we'll solve the linear equations ...

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where a = 1/(4x+3y) and b = 1/(4x-3y)

Dividing the second equation by 2 and adding the first, we have ...

  (7a +4b) +1/2(8b -14a) = (5/4) +1/2(3/2)

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Now, we can get back to solving for x and y.

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  8x = 32 . . . . . . . . . add the two equations

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The solution to the system of equations is (x, y) = (4, 4).

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<em>Additional comment</em>

If you graph these equations, you find they describe hyperbolas that intersect at (0, 0) and (4, 4). The "solution" (0, 0) is extraneous, as both equations are undefined there.

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