Y-y1 = m(x-x1)
y-(-1) = 6 (x- -1)
answer: y = 6x-5
You multiply both of the equations until you have two of the same term the same like for example, say I have 4x and 5x. You want to multiply until both have the same number, so multiply 5x by four, then multiply 4x by five, and you will get 20x, then both of those cancel out and you will be left with the other variable, and you just solve like a normal equation.
T=2
t^2=4
4-4=0
is that right?
I don’t see any question. What is the question.
We can find this integer using a system of equations. The first thing we look at is the first sentence.
Let's call X The first integer,
Let's call Y the second integer.
So, X+Y=61 and X-Y= 1
Using Substituion on the second equation, we get
X=Y+1
(Now we plug in Y+1 into the second equation for X)
So,
(Y+1)+Y=61
2Y=60
Y=30
So, one of the integers is 30.
Now to find the second, we go back to
X=Y+1
X=30+1
X=31.
So, the integers are 31 and 30.
Hope this helps!
