3 years ago

I need help, with this question.

Mathematics

2 answers:

k0ka [10]3 years ago

8 0

The answer is going to be 100

bazaltina [42]3 years ago

8 0

The answer is should be 100

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An apple slice is cut into 6 equal slices as shown below

Oksana_A [137]

Length of the pie = πD

Length of the pie = 10π

One slice = 10π ÷ 6 = 5.25 in (Answer C)

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3 years ago

86,921 in expanded form

Rudik [331]

86921 = 80000 + 6000 + 900 +20 +1

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2 years ago

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Put these in order starting with the smallest.<br>9 3/2 <br>27 1/3 <br>125 2/3

Pepsi [2]

Answer:

second, third,first

Step-by-step explanation:

first

3/2=1.5

9^1.5=27

second

1/3=0.333

27^0.333=3

third

2/3=0.667

125^0.667=25

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3 years ago

Evaluate the expression when b=-3 and x=4.<br> b-5x

Anton [14]

Answer:

-23

Step-by-step explanation:

b - 5x

-3 - 5(4)

-3 - 20

-23

4 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago