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3 years ago

Find the missing side of the triangle

Mathematics

1 answer:

Leona [35]3 years ago

6 0

Answer:

Step-by-step explanation:

Using Pythagoras theorem, we have

x^2+11^2=15^2, x^2=104, x=2*sqrt(26)

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Write an equation in slope for a line that passes through (3,4) (and has a y intercept of -8)

Vlad [161]

Answer:

Part 1) The equation in slope intercept form is $y=4x-8$

Step-by-step explanation:

Part 1) Write an equation in slope-intercept form for a line that passes through (3,4) (and has a y intercept of -8)

we know that

The equation of a line in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$b=-8$

$point\ (3,4)$

substitute

$4=m(3)-8$

solve for m

$4+8=3m$

$3m=12$

$m=4$

therefore

$y=4x-8$

5 0

3 years ago

Juan y maria mezclan cafe de colombia, cafe de brazil, cafe de guinea y cafe de venezuela en paquetes de un kilo. Observa la fra

wel

Answer:

Step-by-step explanation:

Ya que mezclan café colombiano, brasileño, guineano y venezolano en un paquete de un kilo. Igualmente deben agregar los cafés juntos.

Para encontrar la cantidad igual para cada café en 1 kilo, divida 1 kilo y los 4 cafés. Entonces la cantidad sería 1/4 (o 0.25) de café por kilo. La respuesta significa que cada uno de los cuatro cafés pesa 1/4 kilo.

Como cada café representa 1/4 kilo, el café colombiano representa 1/4 kilo.

Si necesita ayuda adicional, comente a continuación.

4 0

3 years ago

How many ounces is the world's Heaviest Car Balanced on the Head?

kolbaska11 [484]

Answer:

My best bet is 5632 ounces if not I'm sorry for my wrong answer.

7 0

3 years ago

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

Position of particle A:-

$x(t)=5t-5$

$y(t)=2t-k$

Position of particles B:-

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

PLEASEE HELP ASAP ILL GIVE BRAINLIST

Gnoma [55]

Answer:

1a) 77 + 84v

1b) 70d + 10m

2a) 96 + 40r

2b) 6p + 8

3a) 27a + 24

3b) 11a + 90

Hope that helps! :)

_Aphrodite

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers