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algol13
4 years ago
13

Which equation is represented by the graph below?

Mathematics
1 answer:
zepelin [54]4 years ago
7 0

Answer: A. y-In x-3

explanation:

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I have 7 students. Two of them love skateboarding, and five love biking. If my number of students doubles, but the ratio of pref
atroni [7]

Answer:

10 (love biking)

Step-by-step explanation:

The ratio is 2(Skateboarding):5(biking) which, when doubled is; 4(skateboarding):10(biking)

5 0
3 years ago
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-8k + 6 = -10k + 10 SOMEONE HELP QUICKKKK
Amiraneli [1.4K]

Answer:

k = 2

Step-by-step explanation:

-8k + 6 = -10k + 10

-8k = -10k +4

2k = +4

2k / 2 = 4 / 2

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3 0
3 years ago
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Explain your answer, please
Molodets [167]

.1.Scale Factor of Triangle STU to Triangle PQR= 1.5

2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2

3. about 90 armadillo

1.Side ST: 15 ÷ Side PQ: 10 = 1.5

2.Side JM: 14 ÷Side EH: 7 = 2

3.843/7=120.428571429

843/4=210.75

210.75-120.428571429=90.321428571

This rounds to 90 armadillo

Hope this helps :3 ❤

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3 years ago
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I need help with this
Monica [59]

Using derivatives, it is found that regarding the tangent line to the function, we have that:

  • The slope is of 962.
  • The equation of the line is y = 962x - 5119.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

The slope of the line tangent to a function f(x) at x = x' is given by f'(x'). In this problem, the function is given by:

f(x) = 5x³ + 2x + 1.

The derivative is given by:

f'(x) = 15x² + 2.

Hence the slope at x = 8 is:

m = f'(8) = 15(8)² + 2 = 962.

The line goes through the point (8,f(8)), hence:

f(8) = 5(8)³ + 2(8) + 1 = 2577.

Hence:

y = 962x + b

2577 = 962(8) + b

b = -5119.

Hence the equation is:

y = 962x - 5119.

More can be learned about tangent lines at brainly.com/question/8174665

#SPJ1

7 0
2 years ago
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