Answer:
<h2>It can have infinitely many dimensions. The area for a rectangle is the product of its width and height (Area = width * height). Therefore, any pair of lengths that yield 400cm2 when multiplied can be its dimensions.</h2>
<h2>400 = 10×40</h2><h2> </h2><h2> = 20×20</h2><h2> </h2><h2> =127.32395×3.14159 </h2>
Step-by-step explanation:
<h3 /><h3>Sana nakatulong ako :-) paki follow nalang Ty </h3>
Answer:
left left right right left right
Step-by-step explanation:
just divide
Answer:
-4-9v
Step-by-step explanation:
Answer:
A and B has the same constant of proportionality
Step-by-step explanation:
![y \propto x](https://tex.z-dn.net/?f=y%20%5Cpropto%20x)
![y = kx ----1](https://tex.z-dn.net/?f=y%20%3D%20kx%20----1)
Where k is the constant of proportionality
We are supposed to find Which relationships have the same constant of proportionality between y and x as in the equation ![y=\frac{1}{2}x](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx)
On comparing with 1
![k = \frac{1}{2}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
A)6y = 3x
![y = \frac{3}{6}x\\y = \frac{1}{2}x](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%7D%7B6%7Dx%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx)
So, this equation has the same constant of proportionality
B)![(x_1,y_1)=(2,1)\\(x_2,y_2)=(4,2)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%282%2C1%29%5C%5C%28x_2%2Cy_2%29%3D%284%2C2%29)
To find the equation :
Formula : ![y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
So, ![y - 1=\frac{2-1}{4-2}(x-2)\\y-1=\frac{1}{2}(x-2)\\y-1=\frac{1}{2}x-1\\y=\frac{1}{2}x](https://tex.z-dn.net/?f=y%20-%201%3D%5Cfrac%7B2-1%7D%7B4-2%7D%28x-2%29%5C%5Cy-1%3D%5Cfrac%7B1%7D%7B2%7D%28x-2%29%5C%5Cy-1%3D%5Cfrac%7B1%7D%7B2%7Dx-1%5C%5Cy%3D%5Cfrac%7B1%7D%7B2%7Dx)
So, this equation has the same constant of proportionality
C)
![(x_1,y_1)=(1,2)\\(x_2,y_2)=(2,4)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%281%2C2%29%5C%5C%28x_2%2Cy_2%29%3D%282%2C4%29)
To find the equation :
Formula : ![y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
So, ![y - 2=\frac{4-2}{2-1}(x-1)\\y - 2=2(x-1)\\y - 2=2x-2\\y=2x](https://tex.z-dn.net/?f=y%20-%202%3D%5Cfrac%7B4-2%7D%7B2-1%7D%28x-1%29%5C%5Cy%20-%202%3D2%28x-1%29%5C%5Cy%20-%202%3D2x-2%5C%5Cy%3D2x)
So, this equation do not has the same constant of proportionality
D)
![(x_1,y_1)=(2,1)\\(x_2,y_2)=(3,2.5)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%282%2C1%29%5C%5C%28x_2%2Cy_2%29%3D%283%2C2.5%29)
To find the equation :
Formula :![y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
So, ![y - 1=\frac{2.5-1}{3-2}(x-2)](https://tex.z-dn.net/?f=y%20-%201%3D%5Cfrac%7B2.5-1%7D%7B3-2%7D%28x-2%29)
![y-1=1.5(x-2)\\y-1=1.5x-3\\y=1.5x-2](https://tex.z-dn.net/?f=y-1%3D1.5%28x-2%29%5C%5Cy-1%3D1.5x-3%5C%5Cy%3D1.5x-2)
So, this equation do not has the same constant of proportionality
Hence A and B has the same constant of proportionality
(i)
∠BAD + ∠ABD + ∠ADB = 180 <em>the sum of the angles of a triangle equals 180°</em>
70 + 50 + ∠ADB = 180 <em>substituted given information</em>
∠ADB = 60 <em>subtraction property (subtracted 70 and 50)</em>
∠ABD + ∠BDC = ∠ADC <em>angle addition property</em>
60 + ∠BDC = 80 <em>substituted solved and given information</em>
∠BDC = 20 <em>subtraction property</em>
(ii) SORRY but I'm not sure how to find ∠BCD. If ∠ADC = ∠ABC, then ∠DBC = 30. We already calculated ∠BDC = 20, which means that ∠BCD = 130
(iii)
∠BCA = ∠ADB <em>given as a hint</em>
∠BCA = 60 <em>substituted ∠ADB that was solved in part (i)</em>
Answer: (i) = 20, (ii) = 130?, (iii) = 60