D = -1<x<5
R = -3<y<3
ps can I have a brainliest
Remember the quadratic formula determinant?
If b^2 -4ac < 0, a complex root exists.
So for this problem, m^2 - 4q is the determinant, and if less than 0, is complex.
So a=-m/2 and b=(1/2)SQRT(m^2 - 4q)
0.8 squares shaded out of 10
You just do 4x2 which is 8
Then add the 0. In front of 8
Easy as that
Step-by-step explanation:
4x-9y=-9 1
2x +3y=3 2
1 - 2(2)
4x -9y=-9
(2)* -4x -6y=6
________
0-15y=-3
15y=3
y=3/15
y=1/5
